Question: What is the total delay (latency) for a frame of size 5 million bits that is being sent on a link with 10 routers each having a queuing time of 2 μs and a processing time of 1 μs. The length of the link is 2000 Km. The speed of light inside the link is 2 × 108 m/s. The link has a bandwidth of 5 Mbps. Which component of the total delay is dominant? Which one is negligible?
Solution:
Given data:
Distance (length of the link) =2000 Km
=2000
Propagation speed=2
Frame size=5million bits
=5000000bits
The Bandwidth=5Mbps
=5
Queuing time=10
=20
Processing delay=10
=10
Total delay (Latency) = Propagation time + Transmission time + Queuing time
+ Processing delay.
Propagation time=
=
= 0.01s
Therefore, Propagation time=0.01s
Transmission time=
=
= 1s
Therefore, Transmission time=1s
Queuing time=10
=10
=20
= 0.00002s
Therefore, Queuing time=0.00002s
Processing delay=10
=10
Therefore, Processing delay=0.000010s
Therefore, Total delay (Latency) =0.01+1+0.000020+0.000010
=1.01003s