**Question: **

** A1 A2**

**B1** .4 .3

**B2** .2 .1

**Determine P(A1 I B1)**

**Determine P(A2 I B1)**

**Did your answers to parts (a) and (b) sum to 1? Is this a coincidence? Explain**

**Solution: ** a. P(A1 I B1) = P( A1 n B1)/ P(B1)

P( A1 n B1) = 0.4

P(B1) = 0.4+0.3 = .7

P(A1 I B1) = 0.4/0.7 = 0.5714

b. P(A2 I B1) = P( A1 n B1)/ P(B1)

P( A2 n B1) = 0.3

P(B1) = 0.4+0.3 = .7

P(A1 I B1) = 0.3/0.7 = 0.4285